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-10x^2-12x+45=-9x^2+1x-5x
We move all terms to the left:
-10x^2-12x+45-(-9x^2+1x-5x)=0
We get rid of parentheses
-10x^2+9x^2-1x+5x-12x+45=0
We add all the numbers together, and all the variables
-1x^2-8x+45=0
a = -1; b = -8; c = +45;
Δ = b2-4ac
Δ = -82-4·(-1)·45
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{61}}{2*-1}=\frac{8-2\sqrt{61}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{61}}{2*-1}=\frac{8+2\sqrt{61}}{-2} $
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